(2+4) 6 byte integer to double

[S R]

There is a DLL on a Windows (Intel, 32-bit) server that contains a functions
called EntConvertInt which takes a Int16 and Int32 arguments and returns a double.

I want to create a Java version of this, but cannot get the numbers to work.

I think the Int16 is the exponent (including the sign bi) and the Int32 is the
mantissa.

I think what the DLL does is convert the ints to binary or Hex, and then moves
the two to a double.

Example of inputs and expected results are:

Int16 Int32 Result
129 0 1
138 369098752 600
29069 379652669 4820.13

I tried converting the inputs to binary (Integer.ParseInt ( x, 2 )),
then joining to two into a string and then using Double.logbitstodouble, but the
result is way out.

I have tried a number of combinations of adjusting taking the 48-bit binary
"string" and then adjusting the size of the exp/mantissa to see which
combination gives the right answer but to no avail.

I need some pointers on how this can be done in Java as I am all out of ideas.

[David Kerber]

[This followup was posted to alt.comp.lang.java and a copy was sent to
the cited author.]

In article <UvRnq.5388$***@newsfe21.ams2>, ***@duz.not.exist.com
says...

Post by S R
There is a DLL on a Windows (Intel, 32-bit) server that contains a functions
called EntConvertInt which takes a Int16 and Int32 arguments and returns a double.
I want to create a Java version of this, but cannot get the numbers to work.
I think the Int16 is the exponent (including the sign bi) and the Int32 is the
mantissa.

If you're not sure, how will you know what you're supposed to be doing?

D